Divide: x^2-3x+2/8x-8 divide x^2-4/5x-10

teevaituinomakw

teevaituinomakw

Answered question

2022-09-03

Divide:
x 2 3 x + 2 / 8 x 8 divide x 2 4 / 5 x 10

Answer & Explanation

Medwsa1c

Medwsa1c

Beginner2022-09-04Added 17 answers

( x 2 3 x + 2 ) / ( 8 x 8 )
factor each term
( x 2 ) ( x 1 ) 8 ( x 1 )
cancel like terms (x-1 cancels)
x 2 8
again assuming you meant
( x 2 4 ) / ( 5 x 10 )
factor each term
( x 2 ) ( x + 2 ) 5 ( x 2 )
cancel like terms (x-2 cancels)
x + 2 5
if the divide was supposed to be (you were very unclear)
( ( x 2 3 x + 2 ) / ( 8 x 8 ) ) / ( ( x 2 4 ) / ( 5 x 10 ) )
you would now have
x 2 8
x + 2 5
which becomes
x 2 8 5 x + 2
nothing can cancel so we have
5 ( x 2 ) 8 ( x + 2 )
Audrey Mckee

Audrey Mckee

Beginner2022-09-05Added 1 answers

x 2 3 x + 2 8 x 8 ÷ x 2 4 5 x 10
( x 2 ) ( x 3 ) 8 ( x 1 ) ÷ ( x + 2 ) ( x 2 ) 5 ( x 1 )
Now, to divide fractions you flip the second fraction and change the sign from divide to multiply
( x 2 ) ( x 3 ) 8 ( x 1 ) 5 ( x 1 ) ( x + 2 ) ( x 2 )
Now since we are multiplying we can cancel the like terms in the numerator and the denominator and then rewrite the expression
( x 3 ) 8 5 ( x + 2 )
5 ( x 3 ) 8 ( x + 2 )

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