\sin(\arccos(\frac{1}{\sqrt3}))=\frac{\sqrt2}{\sqrt3} proof this equation

Turnseeuw

Turnseeuw

Answered question

2022-01-23

sin(arccos(13))=23 proof this equation

Answer & Explanation

vasselefa

vasselefa

Beginner2022-01-24Added 9 answers

Let θ=arccos(13), so cosθ=13
You want to find sinθ
Use sin2θ+cos2θ=1
Roman Stevens

Roman Stevens

Beginner2022-01-25Added 10 answers

sin2(arccos(13))+cos2(arccos(13))=sin2(arccos(13))+13=1
or
Solution sketch: Draw a right triangle, with 1 as the hypotenuse and 13 as one of the legs (or 3 as the hypotenuse and 1 as one of the legs, same thing). Then see what arccos(13) corresponds to in that triangle, then see what sin of that represents. Once you know what you are actually after, you do the calculations.

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