Interval in which (\cos p-1)x^2+\cos p.x+\sin p=0 has real roots The

treslagosnv

treslagosnv

Answered question

2022-01-27

Interval in which (cosp1)x2+cosp.x+sinp=0 has real roots
The solution given in my reference is the interval (0,π)
My Attempt
Δ=cos2p4(cosp1)sinp0
cos2p4sinpcosp+4sinp0
Δ=16sin2p16sinp0sin2psinp

Answer & Explanation

Jaiden Conrad

Jaiden Conrad

Beginner2022-01-28Added 14 answers

Adding to what you did, Let us solve the inequation
sin2psinp
or
sinp(sinp1)0
which yields to
sinp0
because (sinp1)0
the answer is d) 0<p<π

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