Can someone explain why this is true? \int_0^{2\pi}(\sin nx-\sin kx)^2dx=2\pi

Anniyah Povey

Anniyah Povey

Answered question

2022-02-26

Can someone explain why this is true?
02π(sinnxsinkx)2dx=2π

Answer & Explanation

emeriinb4r

emeriinb4r

Beginner2022-02-27Added 10 answers

Proof. Suppose ab; then both ab and a+b are nonzero.
02πsin(ax)sin(bx)dx=02πcos((ab)x)cos((a+b)x)2dx
=12[sin((ab)x)absin((a+b)x)a+b]x=0x=2π
since sinkπ=0. On the other hand, if b=a, then
02πsin2(ax)dx=02π1cos(2ax)2dx
=12[xsin(2ax)2a]x=0x=2π
=π

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