How to evaluate \int_0^{\pi/2}3\cos^2\theta d\theta

Vofteldetgpt

Vofteldetgpt

Answered question

2022-02-25

How to evaluate
0π23cos2θdθ

Answer & Explanation

lucratifar1

lucratifar1

Beginner2022-02-26Added 5 answers

There is a cute trick for this:
I=30π2cos2xdx=30π2sin2dx
by using abf(x)dx=abf(a+bx)dx
Adding gives us
2I=30π2(cos2x+sin2x)dx=30π21dx=3π2
Hence your integral is
3π4

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