Find: \lim_{x\to0}\frac{\frac{\sin x}{x}-\cos x}{2x(\frac{e^{2x}-1}{2x}-1)}

hazardetzt10

hazardetzt10

Answered question

2022-02-26

Find:
limx0sinxxcosx2x(e2x12x1)

Answer & Explanation

Asa Buck

Asa Buck

Beginner2022-02-27Added 8 answers

sin(x)x=1x23!+O(x4)
cos(x)=1x22!+O(x4)
exp(2x)=1+2x+(2x)22!+O(x3)
Hence,
sin(x)xcos(x)exp(2x)12x=x23!+x22!+O(x4)2x2+O(x3)=x23+O(x4)2x2+O(x3)
=13+O(x2)2+O(x)
Hence,
limx0sin(x)xcos(x)exp(2x)12x=16

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