Can anyone offer please help me solve the following trig

Romana Newton

Romana Newton

Answered question

2022-02-25

Can anyone offer please help me solve the following trig identity.
1tan(x2)1+tan(x2)=1sinxcosx=cosx1+sinx

Answer & Explanation

King Osborn

King Osborn

Beginner2022-02-26Added 6 answers

I'm doing it from RHS
1tan(x2)1+tan(x2)=1sinxcosx=cosx1+sinx
=cosx1+sinx
=1tan2(x2)1+tan2(x2)1+2tan(x2)1+tan2(x2)
=1tan2(x2)1+tan2(x2)1+2tan(x2)1+tan2(x2)
=1tan2(x2)1+tan2(x2)+2tan(x2)
=(1tan(x2))(1+tan(x2))(1+tan(x2))2
=(1tan(x2))1+tan(x2)}
=LHS

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?