Prove that \cot^2(\pi/7)+\cot^2(2\pi/7)+\cot^2(3\pi/7)=5

Junaid Ayala

Junaid Ayala

Answered question

2022-02-27

Prove that cot2(π7)+cot2(2π7)+cot2(3π7)=5

Answer & Explanation

lilwayne10j6o

lilwayne10j6o

Beginner2022-02-28Added 8 answers

So:
the roots of z3+z23z1=0 are 2cos2π7,2cos4π7, 2cos6π7
If cot2rπ7=u, cos2rπ7=1tan2rπ71+tan2rπ7=cot2rπ71cot2rπ7+1=u1u+1
2(u1)u+1=2cos2rπ7 will satisfy
(2(u1)u+1)3+(2(u1)u+1)33(2(u1)u+1)1=0
On simplification, 7u335u2+21u1=0 whose roots are cot2rπ7
Now, use Vieta's formulas, to find cot2rπ7=357

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