How do you integrate the following functions: \int(\frac{\cos\theta}{1+\sin^2\theta})^2d\theta

sweetrainyday8s2

sweetrainyday8s2

Answered question

2022-02-26

How do you integrate the following functions:
(cosθ1+sin2θ)2dθ

Answer & Explanation

Capodarcod0f

Capodarcod0f

Beginner2022-02-27Added 6 answers

cos2x(1+sin2x)2dx=sec2x(sec2x+tan2x)dx
=1(2tan2x+1)2d(tanx)
(tanxtanu2)=12sec2usec4udu
=122cos(2u)+1du
=122(sin(2u)2+u)+C
=122(sin(2arctan(2tanx))2+arctan(2tanx))
=tanx2(2tan2x+1)+122arctan(2tanx)+C

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