Prove identity: \(\displaystyle{\sin{\alpha}}={\frac{{{2}{\tan{{\frac{{\alpha}}{{{2}}}}}}}}{{{1}+{{\tan}^{{2}}{\frac{{\alpha}}{{{2}}}}}}}}\) I am having a problem

Asher Olsen

Asher Olsen

Answered question

2022-04-01

Prove identity: sinα=2tanα21+tan2α2
I am having a problem proving this identity. I write tan like sinα2cosα2 and the squared one in the same way. I eventually get
2sinα2cosα2sin2α2+cos2α2

Answer & Explanation

kaosimqu5t

kaosimqu5t

Beginner2022-04-02Added 10 answers

From here
2sinα2cosα2sin2α2+cos2α2
divide by cos2α2
Marquis Ibarra

Marquis Ibarra

Beginner2022-04-03Added 9 answers

In your last formula
Your nominator is sinx due to sin2x=2sinxcosx, written for x2.
Your denominator is 1, due to sin2x+cos2x=1

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