Simplify \arccos{\sqrt{\frac{2}{3}}}-\arccos{\frac{\sqrt6+1}{2\sqrt3}}

tobeint39r

tobeint39r

Answered question

2022-04-27

Simplify arccos{23}arccos{6+123}

Answer & Explanation

Bethany Mills

Bethany Mills

Beginner2022-04-28Added 14 answers

Let
α=arccos23 and β=arccos6+123
so
cosα=23   and   cosβ=6+123
and
sinα=123=13   and   sinβ=17+2612=52612
so
cos(αβ)=236+123+1352612=
=12+2+5266
=23+2+(32)26
=32
so αβ=π6

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?