We have 9+40\sin^2 x=-42\sin x\cos x

yert21trey123z7

yert21trey123z7

Answered question

2022-04-27

We have 9+40sin2x=42sinxcosx

Answer & Explanation

amisayq6t

amisayq6t

Beginner2022-04-28Added 18 answers

We can use the fact that sin2(x)+cos2(x)=1. Multiply both sides by 9 to get 9sin2(x)+9cos2(x). We then have
9sin2(x)+9cos2(x)+40sin2(x)=42sin(x)cos(x)
49sin2(x)+42sin(x)cos(x)+9cos2(x)=0
(7sin(x)+3cos(x))2=0
which gives the desirable equation you want to have.

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