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minwaardekn

minwaardekn

Answered question

2022-06-14

Prove 8 ( 1 cos 2 a ) ( 1 cos 2 b ) ( 1 cos 2 c ) 27 cos a cos b cos c

Answer & Explanation

arhaitategr

arhaitategr

Beginner2022-06-15Added 13 answers

Let u, v and w be lengths-sides of the triangle such that
cos a = v 2 + w 2 u 2 2 v w , cos b = u 2 + w 2 v 2 2 u w , cos c = u 2 + v 2 w 2 2 u v and
let u 2 + v 2 w 2 = r , u 2 + w 2 v 2 = q , v 2 + w 2 u 2 = p
Hence, we need to prove that
8 c y c ( 1 r 2 ( p + r ) ( q + r ) ) 27 p q r ( p + q ) ( p + r ) ( q + r )
or
8 ( p q + p r + q r ) 3 27 p q r ( p + q ) ( p + r ) ( q + r ) .
Let pq=z, pr=y and qr=x.
Hence, we need to prove that
8 ( x + y + z ) 3 27 ( x + y ) ( x + z ) ( y + z ) ,
which is AM-GM:
( c y c ( x + y ) 3 ) 3 c y c ( x + y ) .

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