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freakygirl838w

freakygirl838w

Answered question

2022-06-14

Prove that sin ( x + θ ) sin ( x + ϕ ) = cos ( θ ϕ ) + cot ( x + ϕ ) sin ( θ ϕ )

Answer & Explanation

luisjoseblash2

luisjoseblash2

Beginner2022-06-15Added 16 answers

sin ( x + θ ) sin ( x + ϕ ) = sin [ ( x + ϕ ) + ( θ ϕ ) ] sin ( x + ϕ ) = sin ( x + ϕ ) cos ( θ ϕ ) + sin ( θ ϕ ) cos ( x + ϕ ) sin ( x + ϕ ) = = sin ( x + ϕ ) cos ( θ ϕ ) sin ( x + ϕ ) + sin ( θ ϕ ) cos ( x + ϕ ) sin ( x + ϕ ) = cos ( θ ϕ ) + cot ( x + ϕ ) sin ( θ ϕ )
for the last equality I used cot ( x + ϕ ) = cos ( x + ϕ ) sin ( x + ϕ )
opepayflarpws

opepayflarpws

Beginner2022-06-16Added 7 answers

We have that
sin ( x + θ ) sin ( x + ϕ ) = sin ( ( x + ϕ ) + ( θ ϕ ) ) sin ( x + ϕ ) = sin ( x + ϕ ) cos ( θ ϕ ) + sin ( θ ϕ ) cos ( x + ϕ ) sin ( x + ϕ ) = sin ( x + ϕ ) cos ( θ ϕ ) sin ( x + ϕ ) + sin ( θ ( ϕ ) cos ( x + ϕ ) sin ( x + ϕ ) = cos ( θ ϕ ) + cot ( x + ϕ ) sin ( θ ϕ )
by the angle sum formula.

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