Prove that sin 4 </msup> &#x2061;<!-- ⁡ --> &#x03B8;<!-- θ --> + cos

Izabella Ponce

Izabella Ponce

Answered question

2022-06-24

Prove that sin 4 θ + cos 4 θ = 3 + cos 4 θ 4
By considering ( sin 2 θ + cos 2 θ ) 2 and ( sin 2 θ + cos 2 θ ) 3 prove that
a)  sin 4 θ + cos 4 θ = 3 + cos 4 θ 4 , b)  sin 6 θ + cos 6 θ = 5 + 3 cos 4 θ 8

Answer & Explanation

candelo6a

candelo6a

Beginner2022-06-25Added 24 answers

a) Since sin 2 ( θ ) + cos 2 ( θ ) = 1 we can write: 1 = 1 2 = ( sin 2 ( θ ) + cos 2 ( θ ) ) 2 = cos 4 ( θ ) + sin 4 ( θ ) + 2 sin 2 ( θ ) cos 2 ( θ ). Hence cos 4 ( θ ) + sin 4 ( θ ) = 1 2 sin 2 ( θ ) cos 2 ( θ ) = 1 1 2 sin 2 ( 2 θ ) = 1 1 2 1 cos ( 4 θ ) 2 , the claim follows. b) is similar, even there you just have to remember basic goniometric ids (in particular bisection and dupliaction).
opepayflarpws

opepayflarpws

Beginner2022-06-26Added 7 answers

Hint: For a
L . H . S = sin 4 A + cos 4 A
= ( sin 2 A + cos 2 A ) 2 2 sin 2 A . cos 2 A
= 1 1 4 ( 2 sin A . cos A ) 2
= 1 1 4 sin 2 2 A
= 4 sin 2 2 A 4
= 4 1 + cos 4 A 4
= 3 + cos 4 A 4 = R . H . S
Proved.
Just consider that θ = A
Follow similar steps above for b.

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