I was given a task to prove: sec &#x2061;<!-- ⁡ --> &#x03B8;<!-- θ -->

Jeffery Clements

Jeffery Clements

Answered question

2022-06-25

I was given a task to prove:
sec θ sec θ tan θ = sec θ ( sec θ + tan θ )
Then I replaced them with their Ratio and Reciprocal Identities
sec θ = 1 cos θ tan θ = sin θ cos θ
so I came up with this:
1 cos θ 1 cos θ sin θ cos θ = 1 cos θ ( 1 cos θ + sin θ cos θ )
then,
1 cos θ sin θ cos θ = 1 cos θ ( 1 + sin θ cos θ )
and I had the reciprocal,
1 cos θ cos θ sin θ = 1 cos θ ( 1 + sin θ cos θ )
and I don't know what to do next, can someone explain to me how?

Answer & Explanation

Josie Stephenson

Josie Stephenson

Beginner2022-06-26Added 20 answers

It's wrong.
Here's why:
LHS = sec θ sec θ tan θ = 1 tan θ = adjacent opposite . . . .
RHS = sec θ ( sec θ + tan θ ) = 1 cos θ ( 1 cos θ + sin θ cos θ ) = 1 cos θ ( 1 + sin θ cos θ ) = 1 + sin θ cos 2 θ = hypotenuse + opposite adjacent
Now, for adjacentopposite to be equal to hypotenuse+oppositeadjacent, ‘‘opposite" must be equal to ‘‘adjacent" and ‘‘hypotenuse" must be 0. Since this cannot be true, I suppose it is wrong

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