Consider the space Ł^p(Omega):=(L^p(Omega))^N=L^p(Omega) xx L^p(Omega) xx ... xx L^p(Omega), N >= 1, Omega subset RR^n, as the vectorial L^p space associated to the scalar one.

Matonya

Matonya

Open question

2022-08-13

Consider the space
Ł p ( Ω ) := ( L p ( Ω ) ) N = L p ( Ω ) × L p ( Ω ) × . . . × L p ( Ω ) , N 1 , Ω R n ,
as the vectorial L p space associated to the scalar one.
My questions are:
What is the norm | | | | Ł p and can we relate it to | | | | L p ?
How to apply the Hölder Inequality on
Ω u ( x ) v ( x ) d x ,
where
u Ł q , v Ł p , 1 p + 1 q = 1, u = ( u 1 , . . . , u N ) t , v = ( v 1 , . . . . , v N ) t , u i L q ( Ω ), v i L p ( Ω ), and u ( x ) v ( x ) is the scalar product between?

Answer & Explanation

raffatoaq

raffatoaq

Beginner2022-08-14Added 22 answers

A nice norm is
u L p ( Ω ) N := i = 1 N u i L p ( Ω ) p p .
If R N is any norm on R N , then it is easy to see that u L p ( Ω ) N is equivalent to
u := ( u 1 L p ( Ω ) , . . . , u N L p ( Ω ) ) R N .
In the case of L p ( Ω ) N we had set R N := p .
The Hölder inequality also holds in the following sense: We first use the Hölder-inequality of R N inside the integral and then use the Hölder-inequality for Lebesgue-integrals:
Ω u v   d x Ω u p v q   d x Ω u p p   d x p Ω v q q   d x q =
i = 1 N Ω | u i | p   d x p i = 1 N Ω | v i | q   d x q = i = 1 N u i L p ( Ω ) p p i = 1 N v i L q ( Ω ) q q = u L p ( Ω ) N v L q ( Ω ) N

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