I have the vector vec(c) that is: vec(c) =(sum_(i=1)^n m_i vec r_i)/(sum_(i=1)^n m_i) where vec(r)_i i is a vector and m_i is a scalar I need to proof the folowwing equality for any vector vec(r) sum_(i=1)^n m_i|vec(r)-vec(r)_i|^2=sum_(i=1)^n m_1 |vec(r)_i-vec(c)|+m|vec(r)-vec(c)|^2

cousinhaui

cousinhaui

Answered question

2022-10-23

I have the vector c that is:
c = i = 1 n m i r i i = 1 n m i
where r i is a vector and m i is a scalar
I need to proof the folowwing equality for any vector r
i = 1 n m i | r r i | 2 = i = 1 n m 1 | r i c | 2 + m | r c | 2
and i known that m = i = 1 n m i
I try to replace the vector c in the equality but but i get confused with the vector algebra.

Answer & Explanation

Hilfeform5c

Hilfeform5c

Beginner2022-10-24Added 14 answers

Let us use the property
| x y | 2 = ( x y ) . ( x y ) = | x | 2 2 x . y + | y | 2
LHS reduces to the following
= m | r | 2 2 r . ( 1 n m i r i ) + 1 n m i r i . r i
= m ( | r | 2 2 r . c + | c | 2 ) + 1 n m i ( | r i | 2 | c | 2 )

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