Recent questions in Light and Optics

Light and OpticsAnswered question

ramirezherePYM 2022-11-25

Suppose the distance from the lens system of the eye (cornea + lens) to the retina is 16 mm.

(a) What must the power of the lens be when looking at distant objects?

(b) What must the power of the lens be when looking at an object 18.2 cm from the eye?

(c) Suppose that the eye is farsighted; the person cannot see clearly objects that are closer than 1.0 m. Find the power of the contact lens you would prescribe so that objects as close as 18.2 cm can be seen clearly.

(a) What must the power of the lens be when looking at distant objects?

(b) What must the power of the lens be when looking at an object 18.2 cm from the eye?

(c) Suppose that the eye is farsighted; the person cannot see clearly objects that are closer than 1.0 m. Find the power of the contact lens you would prescribe so that objects as close as 18.2 cm can be seen clearly.

Light and OpticsAnswered question

nuseldW4r 2022-11-25

Find the distributions of the random variables that have each of the following moment generating functions:

$m(t)=\frac{{e}^{t}}{2-{e}^{t}}$

$m(t)=\frac{{e}^{t}}{2-{e}^{t}}$

Light and OpticsAnswered question

Giovanna Shaw 2022-11-24

How can you identify whether a picture is upright or upside down?

Light and OpticsAnswered question

fabianmartinOTQ 2022-11-23

Photons of minimum energy 496 kJ/mol are needed to ionize sodium atoms. Calculate the lowest frequecy of light that will ionize a sodium atom. A1.24×1014 s−1 B1.24×1015 s−1 C2.48×1015 s−1 D2.48×1014 s−1

Light and OpticsAnswered question

Jorge Schmitt 2022-11-23

State the factor(s) that needed to be considered while planning a single slit diffraction experiment, in order to make a diffraction pattern easily visible.

Light and OpticsAnswered question

Jenny Roberson 2022-11-20

Is Heisenberg's Uncertainty Principle applicable to light?

Light and OpticsAnswered question

Audrey Arnold 2022-11-19

What is the experimental evidence that light is an electromagnetic wave?

Light and OpticsAnswered question

charmbraqdy 2022-11-18

I'm having trouble obtaining this formula.

Considering the curvature of the Earth (R is the Earth radius) and a non-vertical direction (zenith angle $\theta $), the relation between h and path length L in the atmosphere is:

$h=L\mathrm{cos}\theta +\frac{1}{2}\frac{{L}^{2}}{R}{\mathrm{sin}}^{2}\theta $

h is the atmosphere's height.

I understand the first term (which due to the inclination) but I can't find a way to get the second term (which is introduced by considering the "roundness" of the Earth)

Any help would be greatly appreciated

Considering the curvature of the Earth (R is the Earth radius) and a non-vertical direction (zenith angle $\theta $), the relation between h and path length L in the atmosphere is:

$h=L\mathrm{cos}\theta +\frac{1}{2}\frac{{L}^{2}}{R}{\mathrm{sin}}^{2}\theta $

h is the atmosphere's height.

I understand the first term (which due to the inclination) but I can't find a way to get the second term (which is introduced by considering the "roundness" of the Earth)

Any help would be greatly appreciated

Light and OpticsAnswered question

Juan Lowe 2022-11-14

Suppose you are measuring double-slit interference patterns using an optics kit that contains the following options that you can mix and match: a red laser or a green laser, a slit width of 0.04 or 0.08 mm; a slit separation of 0.25 or 0.50 mm. Estimate the minimum distance L you can place a screen from the double slit that will give you an interference pattern on the screen that you can accurately measure using an ordinary 30 cm (12 in) ruler.

Light and OpticsAnswered question

figoveck38 2022-11-13

Why do electrons on the surfaces of a lens focus photons instead of scattering them in all directions?

Light and OpticsAnswered question

Hanna Webster 2022-11-10

When parallel rays are refracted/reflected to a point in ray diagrams, we say an image is formed. However practically the real image of a star/celestial body will not be an infinitesimally small point. Is this a breakdown of the model we use as the rays won't be perfectly parallel?

Light and OpticsAnswered question

Aden Lambert 2022-11-09

Can a broken light filter shift the wavelength of light exiting it?

Light and OpticsAnswered question

Siena Erickson 2022-11-08

In all consulted literature, the transfer function of the free space is given as follows:

$\mathrm{exp}(-i{k}_{z}d)=\mathrm{exp}(-i2\pi d\sqrt{1/{\lambda}^{2}-{\nu}_{x}^{2}-{\nu}_{y}^{2}})$

When referring to Fourier Optics, they derive the transfer function from the following equation:

$H({\nu}_{x},{\nu}_{y})=\frac{{f}_{in}(x,y)}{{f}_{out}(x,y)}$

I'm wondering why they do it this way. I thought the transfer function is defined in the frequency domain rather than in the time domain (frequency and space for the fourier optics respectively).

$\mathrm{exp}(-i{k}_{z}d)=\mathrm{exp}(-i2\pi d\sqrt{1/{\lambda}^{2}-{\nu}_{x}^{2}-{\nu}_{y}^{2}})$

When referring to Fourier Optics, they derive the transfer function from the following equation:

$H({\nu}_{x},{\nu}_{y})=\frac{{f}_{in}(x,y)}{{f}_{out}(x,y)}$

I'm wondering why they do it this way. I thought the transfer function is defined in the frequency domain rather than in the time domain (frequency and space for the fourier optics respectively).

Light and OpticsAnswered question

Nicholas Hunter 2022-11-05

How is the Rayleigh criterion connected to the Abbe limit?

Light and OpticsAnswered question

apopiw83 2022-11-04

Why the incessant confusion between diffraction and interference?

Light and OpticsAnswered question

Kamden Larson 2022-10-31

Light incident normally on a grating of total ruled width of $5.1\times {10}^{-3}\text{m}$ with 2520 lines in all. Find out if two sodium lines with wavelengths $5890{\text{A}}^{\circ}$ and $5896{\text{A}}^{\circ}$ can be seen distinctly by the grating.

Light and OpticsAnswered question

Madilyn Quinn 2022-10-29

Recently I've heard that you can't heat up stuff beyond sun's surface temperature using sun+lens combination. It is because you can't transport heat from colder object to a hotter object.

Of course, the bigger lens you use, the closer the heated object gets to the sun's surface temperature. So there's a certain lens size, beyond which you can't get heated object any hotter.

But when I exceed that lens' size... where does the extra heat goes? The lens collects solar power from its entire surface area, and focuses it in one spot. So if you reach certain size you collect lots of solar power, but the heated object doesn't increase the temperature. So where all the extra energy goes?

Of course, the bigger lens you use, the closer the heated object gets to the sun's surface temperature. So there's a certain lens size, beyond which you can't get heated object any hotter.

But when I exceed that lens' size... where does the extra heat goes? The lens collects solar power from its entire surface area, and focuses it in one spot. So if you reach certain size you collect lots of solar power, but the heated object doesn't increase the temperature. So where all the extra energy goes?

Finding good answers to the questions that are related to the physics of light and optics is not easy because these are mostly related to graphic experiments or multimedia experiments. Still, there are also verbal explanations that must be provided. When you need light and optics physics help, start with the verbal aspect of light and optics because if you cannot provide a solution in your own words, the graphs and lab experiments will not help you much. Once you get the text part, continue with the equations and the outcome of your research to get your paper structure accurate.