Choose the point on the terminal side of 0. 0=−60∘(a)(−1,−1)(b)(1,−3)(c)(−3,1)

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vestirme4

2021-10-30

Choose the point on the terminal side of 0.

0 = - 60^{\circ} (a) (- 1, - 1) (b) (1, - \sqrt{3}) (c) (- \sqrt{3}, 1)

Nathanael Webber

Skilled2021-10-31Added 117 answers

As we know from the Trigonometric functions

\tan θ = \frac{y}{x}

\tan - 60^{\circ} = \frac{y}{x}

- \sqrt{3} = \frac{y}{x}

Now check the points whose

\frac{y}{x}

value is equal to

- \sqrt{3}

. Then we can say that the point is on the terminal side of

θ

.
a) For the point (-1, -1)

\frac{y}{x} = \frac{- 1}{- 1} = 1

b)For the point

(1, - \sqrt{3})

\frac{y}{x} = \frac{- \sqrt{3}}{1} = - \sqrt{3}

c)For the point

(- \sqrt{3}, 1)

\frac{y}{x} = \frac{1}{- \sqrt{3}} = - \frac{1}{\sqrt{3}}

So the point b is the terminal side of

θ

.
Results:
B)

(1, - \sqrt{3})

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