Agohofidov6

2021-12-26

How do you find the terminal point on the unit circle determined by $t=5\frac{\pi}{12}$ ?

lovagwb

Beginner2021-12-27Added 50 answers

Explanation:

The arc is$t=\frac{5\pi}{12}$

x-cordinate is :$x=\mathrm{cos}\left(\frac{5\pi}{12}\right)$

y-coordinate:$y=\mathrm{sin}\left(\frac{5\pi}{12}\right)$

Calculator gives$x=\mathrm{sin}\left(\frac{5\pi}{12}\right)=\mathrm{sin}75=0.97$

and$y=\mathrm{cos}75=0.26$

The arc is

x-cordinate is :

y-coordinate:

Calculator gives

and

jean2098

Beginner2021-12-28Added 38 answers

The terminal point on the unit circle has the cosine as x-coordinated and the sine as y-coordinate.

$(\mathrm{cos}\theta ,\text{}\mathrm{sin}\theta )$

In this case$\theta =\frac{5\pi}{12}$

$(\mathrm{cos}\frac{5\pi}{12},\mathrm{sin}\frac{5\pi}{12})$

As$\theta =\frac{5\pi}{12}$ is not one of the special angles, we will use a calcutator to evaluate the cousine and the sine at $\theta =\frac{5\pi}{12}$ .

$\mathrm{cos}\frac{5\pi}{12}={\mathrm{cos}75}^{\circ}\approx 0.2588$

$\mathrm{sin}\frac{5\pi}{12}={\mathrm{sin}75}^{\circ}\approx 0.9659$

Thus the coordinates of the terminal point at$\theta =\frac{5\pi}{12}$ are then:

$(\mathrm{cos}\frac{5\pi}{12},\mathrm{sin}\frac{5\pi}{12})=(0.2588,0.9659)$

In this case

As

Thus the coordinates of the terminal point at

nick1337

Expert2022-01-08Added 777 answers

Maybe this will help me, thanks

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