How do you find the terminal point on the unit circle determined by t=5π12 ?

Question

lovagwb · Accepted Answer

Explanation:  The arc is t=5π12  x-cordinate is : x=cos⁡(5π12)  y-coordinate: y=sin⁡(5π12)  Calculator gives x=sin⁡(5π12)=sin⁡75=0.97  and y=cos⁡75=0.26

jean2098 · Accepted Answer

The terminal point on the unit circle has the cosine as x-coordinated and the sine as y-coordinate.

(\cos θ, \sin θ)

In this case

θ = \frac{5 π}{12}

(\cos \frac{5 π}{12}, \sin \frac{5 π}{12})

As

θ = \frac{5 π}{12}

is not one of the special angles, we will use a calcutator to evaluate the cousine and the sine at

θ = \frac{5 π}{12}

.

\cos \frac{5 π}{12} = {\cos 75}^{\circ} \approx 0.2588

\sin \frac{5 π}{12} = {\sin 75}^{\circ} \approx 0.9659

Thus the coordinates of the terminal point at

θ = \frac{5 π}{12}

are then:

(\cos \frac{5 π}{12}, \sin \frac{5 π}{12}) = (0.2588, 0.9659)

nick1337 · Accepted Answer

Maybe this will help me, thanks

How do you find the terminal point on the unit

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