Prove ((cscx-cotx)(cscx+cotx))/secx=cosx

hexacordoK

hexacordoK

Answered question

2021-01-28

Prove (cscxcotx)(cscx+cotx)secx=cosx

Answer & Explanation

Nathanael Webber

Nathanael Webber

Skilled2021-01-29Added 117 answers

LHS=csc2xcot2secx(derence of two)
=1/secx(formula 1+cot2x=csc2x,thus cscxcot2x=1)
=cosx=RHS

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