How can I simply this : (omega sin(omega t)tan(omega t)+omega(cos(omega t)+1) sec^2(omega t))/((cos(omega t)+1)^2)

Jenny Roberson

Jenny Roberson

Answered question

2022-11-12

Simplifying ω sin ( ω t ) tan ( ω t ) + ω ( cos ( ω t ) + 1 ) sec 2 ( ω t ) ( cos ( ω t ) + 1 ) 2

Answer & Explanation

Stella Andrade

Stella Andrade

Beginner2022-11-13Added 19 answers

ω sin ( ω t ) tan ( ω t ) + ω ( cos ( ω t ) + 1 ) sec 2 ( ω t ) ( cos ( ω t ) + 1 ) 2 , sec ( ω t ) = 1 cos ( ω t ) , tan ( ω t ) = sin ( ω t ) cos ( ω t ) , ω sin ( ω t ) tan ( ω t ) + ω ( cos ( ω t ) + 1 ) sec 2 ( ω t ) ( cos ( ω t ) + 1 ) 2 = ω sin 2 ( ω t ) cos ( ω t ) + ω ( cos ( ω t ) + 1 cos 2 ( ω t ) ) ( cos ( ω t ) + 1 ) 2 = = ω sin 2 ( ω t ) cos ( ω t ) cos 2 ( ω t ) + ω ( cos ( ω t ) + 1 cos 2 ( ω t ) ) ( cos ( ω t ) + 1 ) 2 = ω ( 2 cos ( ω t ) cos 3 ( ω t ) + 1 ) cos 2 ( ω t ) ( cos ( ω t ) + 1 ) 2 . ( 1 )
If we will multiply that we must get on the expression ( 1 + cos ( ω t ) ( 1 + cos ( ω t ) , therefore, the result will be:
ω ( cos 2 ( ω t ) + cos ( ω t ) + 1 ) 1 + cos ( ω t ) = ω ( cos 2 ( ω t ) + cos ( ω t ) + 1 cos 3 ( ω t ) + cos 2 ( ω t ) + cos ( ω t ) ) ( 1 + cos ( ω t ) ) 2 = = ω ( 1 cos 3 ( ω t ) + 2 cos ( ω t ) ) ( 1 + cos ( ω t ) ) 2 . ( 2 )
As we can see in (2) the multiplier cos 2 ( ω t ) is absent, therefore, the misprint takes a place.

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