Sound level L_P in units of decibles (dB)is determined by: L_P = 20log_(10)(P/(P_(0))) where p is the sound pressure of the sound, and p_0 = 20 * 10^(-6) Pa is a referencesound pressure (the sound pressure when L_P = 0dB). Determine the sound pressure of 90 dB noise (noisegenerated by a passing truck). By how many times the soundpressure of the truck is larger (louder) than the sound pressureduring normal conversation where the loudness is 65 dB?

comAttitRize8

comAttitRize8

Answered question

2022-07-26

Sound level L P in units of decibles (dB)is determined by:
L P = 20 log 10 ( P P 0 )
where p is the sound pressure of the sound, and p 0 = 20 10 6 P a is a reference sound pressure (the sound pressure when L P = 0 d B). Determine the sound pressure of 90 dB noise (noisegenerated by a passing truck). By how many times the soundpressure of the truck is larger (louder) than the sound pressureduring normal conversation where the loudness is 65 dB?

Answer & Explanation

Urijah Hahn

Urijah Hahn

Beginner2022-07-27Added 13 answers

L p = 20 log ( P / 20 10 6 ) = 90
so, log ( P / 20 10 6 ) = 4.5
so, P = 0.6325 Pa
L p = L p (truck) - L p (norm.conv.)
so,
90 65 = 20 log ( P t / P n c )
so,
P / P c = 10 1.75 = 56.234 times

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