I've been trying to find a rig-like structure (a set R with a monoid structure (R,\cdot,1) and
Sallie Banks
Answered question
2022-01-13
I've been trying to find a rig-like structure (a set R with a monoid structure and a (commutative) monoid structure such that the multiplication distributes over addition) in which 0 is not an absorber with respect to multiplication, i.e. for some . It should be possible to construct such a structure since you have to require absorption as a separate axiom in a rig. So far I haven't been successful as I don't have any experience with rigs but maybe someone else has a neat idea?
Answer & Explanation
yotaniwc
Beginner2022-01-14Added 34 answers
Step 1
Let be a commutative monoïd such that
for all
(for example, you can start with any Boolean ring . Concrete example are given, by for any nonempty set I, for example)
Then set and .
Hence is a commutative monoïd. Moreover, for all , we have
and
,
so you have the distributivity property. Now
for all .
hysgubwyri3
Beginner2022-01-15Added 43 answers
Step 1
Let E be the set of intervals of the real line of the form where and .
Define
and
.
One can check that ( and are abelian monoids, both having identity , and furthermore distributes over .
If it had an absorbing zero element, it would be a full-fledged semiring... but it obviously does not, since the identity is the same as the identity, it is obviously not absorbing.