gabolzm6d
2022-04-16
entreblogsmc2j
Beginner2022-04-17Added 10 answers
If one has a homomorphism of two rings R,S, and R has an identity, then the identity must be mapped to an idempotent element of S, because the equation is preserved under homomorphisms. Now 5 is not an idempotent element in , so the map generated by is not a homomorphism.
However, 10 is an idempotent element of . In particular, the subring generated by 10 has unit 10. Since it is annihilated by 3, and consequently by 18, there is a unital homomorphism (i.e., mapping 1 to 10). So your second map is a legitimate homomorphism of rings (composing with the injection ).
Basically, the point of this answer is to check that one of your maps preserves the relations of the two rings, while the other doesn't.
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