A clean nickel surface (work function 5.1eV), is exposed to light of wavelength 206nm. What is the maximum speed of the photoelectrons emitted from this surface?

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moodleacnn · Accepted Answer

An electron of the metal can receive photon energy from incident light, which is equal to the planck&#039;s constant times the light&#039;s frequency.Since wavelength is given here, frequency =  velocity of light/wavelength.The photoelectric equation mentioned above can be used to determine the photoelectrons&#039; top speed. Under the assumption that the whole  photon energy is used up First -in taking out  electron from the metal  (work function)Secondly -the left over is provided as the kinetic energy to the photo-electronWhen one puts  in the numbers ,the maximum speed can be of the order of             10      5                      meters                    s            .      V          (      m      )        =                            2          M                          (                                    h              c                        λ                    )                -        5.1                  eV                    where:       M    =          mass of electron        =    9.11    ×          10              -        31                           kg            h    =          Planck&#039;s  Constant        =    6.63    ×          10              -        34                           Js            c    =          speed of light        =    3    ×          10      8                               ms                    -        1                  λ    =          wavelength of light        =    206                 nm

A clean nickel surface (work function 5.1eV), is exposed to light of wavelength 206nm. What is the maximum speed of the photoelectrons emitted from this surface?

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