How to solve 2x^2−7x+3=0 by completing the square.

inimigurhkg

inimigurhkg

Answered question

2023-02-25

How to solve 2x2-7x+3=0 by completing the square.

Answer & Explanation

Cailyn Knight

Cailyn Knight

Beginner2023-02-26Added 7 answers

Calculate the quadratic equation's roots.
Given: 2x2-7x+3=0
2(x2-72x)+3=0
Making a perfect square by adding and subtracting 2742
2x2-72x+742-2742+3=0
2x-742-498+3=0
2x-742=258
x-742=2516
x-74=±54
x=±54+74
x=3or12
Hence, the roots of 2x2-7x+3=0are 3and 12.

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