Find the least number which when divided by 6,15,18 leave remainder 5 in each case.

Kendall Murray

Kendall Murray

Answered question

2023-03-23

Find the least number which when divided by 6,15,18 leave remainder 5 in each case.

Answer & Explanation

Tripp Roberson

Tripp Roberson

Beginner2023-03-24Added 6 answers

Find the LCM of given numbers
Given numbers: 6,15,18 can be expressed as the prime factors
6=2×315=3×5and18=2×3×3
LCM6,15,18=2×3×3×5=90.
The number that is 5 more than the LCM the specified numbers will result in a remainder of 5 when divided by these numbers.
So, the required number is 90+5=95.
Therefore, when 95 is divided by the given numbers, it will leave a remainder of 5.

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