waigaK
2021-04-25
toroztatG
Skilled2021-04-27Added 98 answers
Step 1
the equation's solution
It is clear that the auxiliary equation holds true with the help of synthetic division.
(Set each factor equal to 0)
or or
Step 2
Whose roots , may be obtained by synthetic division. Then the general solution is seen to be
Therefore the solution is
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