Use Cramer's rule to solve the given system of linear equations. x_{1}-x_{2}+4x_{3}=-2 -8x_{1}+3x_{2}+x_{3}=0 2x_{1}-x_{2}+x_{3}=6

DofotheroU

DofotheroU

Answered question

2021-03-10

Use Cramer's rule to solve the given system of linear equations.

x1-x2+4x3=-2

-8x1+3x2+x3=0

Answer & Explanation

Isma Jimenez

Isma Jimenez

Skilled2021-03-12Added 84 answers

Step 1
Solution:
Consider the given system is
x1x2+4x3=2
8x1+3x2+x3=0
2x1x2+x3=6
We have Cramer's Rule for solving the system of equations
x=DxD,y=DyD and z=DzD
Where D stands for determinant and rest are to be found as
Dx=|214031611|=2(3+1)+1(06)+4(018)=86 72=86
Dy=|124801261|=1(06)+2(82)+4(480)=620192=218
Dz=|112830216|=1(180)+1(480)2(86)=304
=34
D=|114831211|=1(3+1)+1(82)+4(86)=410+8=2
Step 2
Therefore
x=DxD=862=43
y=DyD=2182=109
z=DzD=342=17

Jeffrey Jordon

Jeffrey Jordon

Expert2021-11-19Added 2605 answers

Answer is given below (on video)

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