Use the given conditions to write an equation for the line in point-slope form and in slope-intercept form. Passing through (3,-1) and perpendicular to the line whose equation is x-9y-5=0 Write an equation for the line in point-slope form and slope-intercept form.

nicekikah

nicekikah

Answered question

2021-06-02

Use the given conditions to write an equation for the line in point-slope form and in slope-intercept form.
Passing through (3,-1) and perpendicular to the line whose equation is x-9y-5=0
Write an equation for the line in point-slope form and slope-intercept form.

Answer & Explanation

brawnyN

brawnyN

Skilled2021-06-03Added 91 answers

Step 1
We find the slope of x9y5=0 by writing it in y=mx+b form
x9y5=0
9y=x5
y=x59
y=19x59
m=19
So, slope of the perpendicular =9
Step 2
Given that the line is passing through (3,-1)
And we got slope =9
So point slope form is:
y(1)=9(x3)
y+1=9(x3)
Step 3
Using the point slope form we find the slope intercept form
y(1)=9(x3)
y+1=9(x3)
y+1=9x+27
y=9x+26
Answer: Point slope: y+1=9(x3)
Slope intercept: y=9x+26

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