The equation (x+1)^{2}-5(x+1)+6=0 is of ? type. To solve the equation, we set W = ?. The resulting quadratic equation us ?.

Phoebe

Phoebe

Answered question

2021-05-23

The equation (x+1)25(x+1)+6=0 is of ? type. To solve the equation, we set W = ?. The resulting quadratic equation us ?.

Answer & Explanation

odgovoreh

odgovoreh

Skilled2021-05-24Added 107 answers

Step 1
Given that :
The equation is (x+1)25(x+1)+6=0.
Step 2
The equation (x+1)25(x+1)+6=0 is of the type ax2+bx+c=0.
To solve the equation,
Set,
w=(x+1)25(x+1)+6
=x2+2x+15x5+6
=x23x+2
To get,
W=x23x+2
The resulting quadratic equation is x23x+2=0.
Jeffrey Jordon

Jeffrey Jordon

Expert2021-11-19Added 2605 answers

Answer is given below (on video)

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