sanuluy

2021-05-08

Factor completely.

(a)$3{x}^{3}-2{x}^{2}-6x+4$

(b)${x}^{2}-7x-18$

(a)

(b)

Delorenzoz

Skilled2021-05-09Added 91 answers

Step 1

a.

Factorization,

$3{x}^{3}-2{x}^{2}-6x+4=(3{x}^{3}-2{x}^{2})-(6x-4)$

$={x}^{2}(3x-2)-2(3x-2)$

$=({x}^{2}-2)(3x-2)$

Step 2

b.

Factorization,

${x}^{2}-7x-18={x}^{2}-9x+2x-18$

=x(x-9)+2(x-9)

=(x+2)(x-9)

a.

Factorization,

Step 2

b.

Factorization,

=x(x-9)+2(x-9)

=(x+2)(x-9)

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