4(3^2x+1)+17(3^x)=7

facas9

facas9

Answered question

2021-06-03

4(32x+1)+17(3x)=7

Answer & Explanation

SoosteethicU

SoosteethicU

Skilled2021-06-04Added 102 answers

We receive:4(32x+1)+17(3x)=7
Rewrite 32x+1 as 32x×3 so that: 4(32x(3))+17(3x)=7
12(32x)+17(3x)=7
Let u=3x so that
12u2+17u=7
12u2+17u7=0
Factor the left side: (3u1)(4u+7)=0
By zero-product property, u=13,(74)
Solve for 3x=u:

3x=13 

3x=(74)
3x=31 no solution as 3x>0
x=1
So, the solution of the equation is: x=1

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?