OlmekinjP

2021-02-25

Now that I know how to solve radical equations, I can use models that are radical functions to determine the value of independent variable when a function value is known.
We need to determine whether this statement makes sense or not.

Aubree Mcintyre

Skilled2021-02-26Added 73 answers

Yes, the statement makes sense. If we know the value of a radical function, we can determine the value of the independent variable using the function value.

Example,

$\sqrt{(\sqrt{x})}=2$

taking${4}^{\frac{1}{2}}$ power on both sides, we have

$(\sqrt{(\sqrt{x})}{)}^{4}={2}^{4}$

$(x)=16$

Since we knew the value of the radical function, we could calculate the value of the independent variable.

Example,

taking

Since we knew the value of the radical function, we could calculate the value of the independent variable.

$\frac{20b}{{\left(4{b}^{3}\right)}^{3}}$

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B) 0

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