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2021-01-31

Completely simplify the expression $(2\frac{x}{{y}^{-1/3}}{)}^{-1}$
Your final answer should contain no negative exponents and no radicals.

doplovif

Skilled2021-02-01Added 71 answers

For negative in exponent, we can change the side of the term

$(2\frac{x}{{y}^{-1/3}}{)}^{-1}$

$=(2x{y}^{\frac{1}{3}}{)}^{-1}$

Then distribute -1 with other exponents

$={2}^{-1}{x}^{-1}({y}^{\frac{1}{3}}{)}^{1}$

$=\frac{1}{2}\cdot \frac{1}{x}{y}^{-\frac{1}{3}}$

$=\frac{1}{2x{y}^{\frac{1}{3}}}$

Answer:$=\frac{1}{2x{y}^{\frac{1}{3}}}$

Then distribute -1 with other exponents

Answer:

$\frac{20b}{{\left(4{b}^{3}\right)}^{3}}$

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