Nannie Mack

2021-01-23

Put each fractional expression into standard form by rationalizing the denominator.
Gives the fraction $\frac{9}{4th\text{}root}(2).$ Should I be multiplying the fraction by the starting denminator, or should I change the exponents?

Brittany Patton

Skilled2021-01-24Added 100 answers

To get rid of 4th root you need three more 2s.

So we have to multiply numerator and denominator by$\sqrt[2\times 2\times 2]{}$

Answer:$\frac{(9)(4throot)(8)}{2}$

$\frac{9}{\sqrt[4]{2}}$

$=\frac{9\times \sqrt[4]{2\times 2\times 2}}{\sqrt[4]{2}\times \sqrt[4]{2\times 2\times 2}}$

$=\frac{9\times \sqrt[4]{2\times 2\times 2}}{\sqrt[4]{2}\times 2\times 2\times 2}$

$\frac{9\times \sqrt[4]{8}}{\sqrt[4]{{2}^{4}}}$

$\frac{9\sqrt[4]{8}}{2}$

Answer:$\frac{9\sqrt[4]{8}}{2}$

So we have to multiply numerator and denominator by

Answer:

Answer:

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