Phoebe

2021-08-17

To calculate: Percentage of gene combinations that result in albino coloring, further model a polynomial representing possible gene combinations.

smallq9

Skilled2021-08-18Added 106 answers

Step 1

a) Punnet square implies that there are 4 total gene combinations, namely NN, Na, Na, aa.

One one gene combination is devoid of even a single N.

Therefore the probability of albino coloring$=\frac{1}{4}$

$=0.25$

Percentage of albino coloring$=25\mathrm{\%}$

b) Each parent deer has half N genes and half a genes.

Modeling genetic makeup of each parent

$=0.5N+0.5a$

As there are two parents, genetic makeup of offspring is modeled in the form of polynomial$(0.5N+0.5a)}^{2$

$={\left(0.5N\right)}^{2}+{\left(0.5a\right)}^{2}+2\left(0.5N\right)\left(0.5a\right)$ (Standard algebraic identity)

$=0.25{N}^{2}+0.25{a}^{2}+2\left(0.5N\right)\left(0.5a\right)$ (Evaluate powers)

$=0.25{N}^{2}+0.25{a}^{2}+0.5\left(Na\right)$ (Simplify)

Coefficients in above polynomial represent the probabilities of each kind of offspring.

a) Punnet square implies that there are 4 total gene combinations, namely NN, Na, Na, aa.

One one gene combination is devoid of even a single N.

Therefore the probability of albino coloring

Percentage of albino coloring

b) Each parent deer has half N genes and half a genes.

Modeling genetic makeup of each parent

As there are two parents, genetic makeup of offspring is modeled in the form of polynomial

Coefficients in above polynomial represent the probabilities of each kind of offspring.

$\frac{20b}{{\left(4{b}^{3}\right)}^{3}}$

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