djeljenike

2021-08-20

To calculate: The equations modeling the word problem that states that subtraction of the second number from three times the first number gives 1 and addition of the first number with twice the second number gives 12 and the solution to the system of equations.

Sally Cresswell

Skilled2021-08-21Added 91 answers

Calculation:

Let the first number be x and the second number be y.

Subtraction of the second number from three times the first number gives 1. This gives the equation as:

$3x-y=1$

Addition of the first number and twice the second number gives 12. This gives the equation as:

$x+2y=12$

Multiply equation$3x-y=1$ by 2

$6x-2y=2$

Add equations$x+2y=12$ and $6x-2y=2$ to obtain:

$x+2y+6x-2y=12+2$

$7x=14$

$x=2$

Substitute the value of x in equation$3x-y=1$ to obtain:

$6-y=1$

$y=5$

Thus, the systems of equation are$3x-y=1$ and $x+2y=12$ . Solution of the equations is $(x,y)=(2,5)$ .

Let the first number be x and the second number be y.

Subtraction of the second number from three times the first number gives 1. This gives the equation as:

Addition of the first number and twice the second number gives 12. This gives the equation as:

Multiply equation

Add equations

Substitute the value of x in equation

Thus, the systems of equation are

$\frac{20b}{{\left(4{b}^{3}\right)}^{3}}$

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