To solve: The equation E=IZ for given I=10+4i, E=88+128i

cistG

cistG

Answered question

2021-08-14

To solve:
The equation E=IZ for given I=10+4i,E=88+128i

Answer & Explanation

joshyoung05M

joshyoung05M

Skilled2021-08-15Added 97 answers

1) Concept: Mathematical modeling is the application of the mathematical concepts in various field of study and also in daily practical side of finding solutions for various problems.
In Ohm's law E=IZ any of the unknown value can be found provided the value of the others two.
i.e. E=IZ
I=EZ
Z=EI
2) Calculation:
Given,
I=10+4i,E=88+128i
E=IZ
Dividing both sides on I
EI=IZZ
EI=Z
Z=EI
On substituting the values of E and I
Z=88+128i10+4i
=2(44+64i)2(5+2i)
=44+64i5+2i
Multiplying the conjugate 52i by the denominator with both the numerator and with the denominator
=44+64i5+2i×52i52i
=(44+64i)(52i)(5+2i)(52i)
Multiply each term of the first factor with each term of the factor in the numerator.
=445+44(2i)+64i5+64i(2i)(5+2i)(52i)
=22088i+320i128i2(5+2i)(52i)
=22088i+320i128(1)(5+2i)(52i)
=22088i+320i+128(5+2i)(52i)
Combining the real and imaginary parts
=(220+128)+(320i88i)(5+2i)(52i)
=348+232i(5+2i)(52i)
Applying the rule for the product of sum and difference of two terms (a+b)(ab)=a2+b2
=348+

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?