CheemnCatelvew

2021-08-11

For each of the models listed below, predict y when x=2.

a)$y\u02c6=1.2+0.8\mathrm{log}x$ ,

b)$\mathrm{log}y\u02c6=1.2+0.8x$ ,

c)$\mathrm{ln}y\u02c6=1.2+0.8\mathrm{ln}x$ ,

d)$y\u02c62=1.2+0.8x$ ,

e)$1y\u02c6\surd =1.2+0.8x$

a)

b)

c)

d)

e)

Brighton

Skilled2021-08-12Added 103 answers

We just need to plug x=2 into each equation.

a)$y=1.2+0.8\mathrm{log}2\sim 1.44$

b)$\mathrm{log}y=1.2+0.8\cdot 2=2.8\to y\to {10}^{2.8}\sim 630.96$

c)$\mathrm{ln}y=1.2+0.8\cdot \mathrm{ln}2=1.2+{\mathrm{ln}2}^{0.8}\to y={e}^{1.2}+{\mathrm{ln}2}^{0.8}={2}^{0.8}\left({c}^{1.2}\right)\sim 5.78$

d)${y}^{2}=1.2+0.8\cdot 2=2.8\to y=\pm \sqrt{2.8}\sim \pm 1.67$

e)$\frac{1}{\sqrt{y}}=1.2+0.8\cdot 2=2.8\to \sqrt{y}=\frac{1}{2.8}\to y=\frac{1}{{2.8}^{2}}\sim 0.13$

a)

b)

c)

d)

e)

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