To calculate: The product of [x-(3-i)][x-(3+i)]

iohanetc

iohanetc

Answered question

2021-08-16

To calculate: The product of [x(3i)][x(3+i)]

Answer & Explanation

oppturf

oppturf

Skilled2021-08-17Added 94 answers

Step 1
Polinomial identity:
1) (a+b)(ab)=a2b2
2) (ab)2=a22ab+b2
Associative property, (a+b)+c=a+(b+c)
Step 2
If P(x) represents the give nexpression, then
P(x)=[x(3i)][3(3+i)]
P(x)=(x3+i)(x3i)
Use associative property of algebraic expressions,
Associative property is written as,
(a+b)+c=a+(b+c)
This property modifies the expressionas,
P(x)=((x3)+i)((x3)i)
Apply arithmetic rule.
(a+b)(ab)=a2b2
Here,
a=(x3), b=(i)
Hence,
P(x)=(x3)2i2
Apply arithmetic rule:
(ab)2=a22ab+b2
Here, NKS a=x, b=3
Since (i)2=(1), the expression becomes,
P(x)=(x3)2i2
=x26x+9+1
=x26x+10
Hence, the product of [x(3i)][x(3+i)] is x26x+10
Jeffrey Jordon

Jeffrey Jordon

Expert2022-07-07Added 2605 answers

Answer is given below (on video)

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