babeeb0oL

2021-09-22

Solve each equation.

${n}^{2}+7n-44=0$

grbavit

Skilled2021-09-23Added 109 answers

Step 1

Consider the provided equation,

${n}^{2}+7n-44=0$

Solve the provided equation.

We know that the provided equation is quadratic equation.

So, for solving the above equation we apply the quadratic formula.

$n}_{1,2}=\frac{-b\pm \sqrt{{b}^{2}-4ac}}{2a$

Here a=1, b=7 and c=-44.

Step 2

So, put the above values in the above formula.

$n}_{1,2}=\frac{-7\pm \sqrt{{7}^{2}-4\cdot 1\cdot (-44)}}{2\cdot 1$

$n}_{1,2}=\frac{-7\pm 15}{2\cdot 1$

$n}_{1}=\frac{-7+15}{2\cdot 1},{n}_{2}=\frac{-7-15}{2\cdot 1$

n=4, n=-11

Hence, the solution the provided equation is n=4, n=−11.

Consider the provided equation,

Solve the provided equation.

We know that the provided equation is quadratic equation.

So, for solving the above equation we apply the quadratic formula.

Here a=1, b=7 and c=-44.

Step 2

So, put the above values in the above formula.

n=4, n=-11

Hence, the solution the provided equation is n=4, n=−11.

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