First use the discriminant to determine whether the equation has two nonreal com

zi2lalZ

zi2lalZ

Answered question

2021-09-16

First use the discriminant to determine whether the equation has two nonreal complex solutions, one real solution with a multiplicity of two, or two real solutions. Then solve the equation.
4x2+20x+25=0

Answer & Explanation

cyhuddwyr9

cyhuddwyr9

Skilled2021-09-17Added 90 answers

Step 1
Given equation is:
4x2+20x+25=0
We know determinant D of a quadratic equation of the form
ax2+bx+c=0 is give by:
D=b24ac
Given equation is: 4x2+20x+25=0,a=4,b=20,c=25
D=b24ac
D=2024(4)(25)
D=400400
D=0
As discriminant is Zero ,given equation has a real solution with multiplicity 2.
4x2+20x+25=0
On simplifying further we get:
4x2+10x+10x+25=0
2x(2x+5)+5(2x+5)=0
(2x+5)(2x+5)=0
(2x+5)2=0x=52.
Step 2
Result:
Required solution is:
x=52.

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