Solve the equation:\sin \frac{x}{3}=\frac{1}{2}, 0\leq x < 2\pi.

slaggingV

slaggingV

Answered question

2021-09-16

Solve the equation:
sinx3=12,0x<2π.

Answer & Explanation

Aniqa O'Neill

Aniqa O'Neill

Skilled2021-09-17Added 100 answers

Step 1
Given: sinx3=12,0x<2π
To find- The value of the above expression.
Concept used- The above expression can be solved by taking sin inverse both sides and solving accordingly.
Step 2
Explanation- Rewrite the given expressions,
sinx3=12
Now taking sin inverse both sides, we get,
sin1(sinx3)=sin1(12)
x3=π6,5π6
Taking on by one and solving further,
x3=π6
x=3π6
x=π2
Step 3
Similarily taking another and solving further,
x3=5π6
x=35π6
x=5π2
So, the values of x are π2,5π2.
Answer- Hence, the values the values of x of the equation sinx3=12 are π2,5π2.

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