rocedwrp

2021-09-20

Solve the equation.

$\sqrt{7x+2}+x=6$

curwyrm

Skilled2021-09-21Added 87 answers

Step 1

We have to solve the given equation

The equation is

$\sqrt{7x+2}+x=6$

Step 2

We have

$\sqrt{7x+2}+x=6$

we can write it as

$\sqrt{7x+2}=6-x$

Now take squares on both sides

$\left(\sqrt{7x+2}\right)}^{2}={(6-x)}^{2$

$7x+2={6}^{2}-2\cdot 6\cdot x+{x}^{2}$

$7x+2=36-12x+{x}^{2}$

take everything on one side

$0={x}^{2}-12x-7x+36-2$

$0={x}^{2}-19x+34$

split the middle term

${x}^{2}-17x-2x+34=0$

x(x-17)-2(x-17)=0

(x-17)(x-2)=0

(x-17)=0 Or (x-2)=0

x=17 Or x=2

Answer:

x=17 Or x=2

We have to solve the given equation

The equation is

Step 2

We have

we can write it as

Now take squares on both sides

take everything on one side

split the middle term

x(x-17)-2(x-17)=0

(x-17)(x-2)=0

(x-17)=0 Or (x-2)=0

x=17 Or x=2

Answer:

x=17 Or x=2

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