Identify the surface whose equation is given. 2r^{2}+z^{2}

rocedwrp

rocedwrp

Answered question

2021-09-15

Identify the surface whose equation is given.
2r2+z2=1

Answer & Explanation

Tasneem Almond

Tasneem Almond

Skilled2021-09-16Added 91 answers

Once again use tha fact that r2=x2+y2. Then, rewriting the equation gives us:
2x2+2y2+z2=1
This is an ellipsoid centered at the origin and its points of interception being:
x=y=±22 and z=0. The ellipsoids

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