Solve for xx. \log_2(x)+\log_2(x−12)=6

chillywilly12a

chillywilly12a

Answered question

2021-11-10

Solve for xx.
log2(x)+log2(x12)=6

Answer & Explanation

Szeteib

Szeteib

Skilled2021-11-11Added 102 answers

Step 1
The given equation is log2(x)+log2(x12)=6
Solve the above equation as follows.
log2(x)+log2(x12)=6
log2(x(x12))=6       (loga(m)+loga(n)=loga(mn))
x(x12)=26
x212x64=0
x216x+4x64=0
x(x16)+4(x16)=0
(x16)(x+4)=0
x=16 or x=−4
Note that negative numbers are not possible i the domain of logarithms.
Thus, the solution is x=16.

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