Suman Cole
2021-11-10
Nathanael Webber
Skilled2021-11-11Added 117 answers
Step 1
Given:
a) The z-score is the value decreased by the mean, divivded by the standard deviation.
Determine the corresponding probability using the normal probability table in the appendix.
Thus 9.18% of the people are expected to have an IQ less than 80.
Step 2
b) The z-score is the value decreased by the mean, divivded by the standard deviation.
Determine the corresponding probability using the normal probability table in the appendix.
c) The boundary of the top 2% has the property that
Determine the critical value corresponding with a probability of 98% or 0.98 using the normal probability table in the appendix. We note that the closest probability 0.9798 is given in the row starting with "2.0" and in the column starting with "0.05:
The corresponding value is then obtained by adding the product of the z-score and the standard deviation to the mean:
Thus the top 2% have an IQ of at least 130.75.
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